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Circle Theorems: Definition and Examples | EDU.COM

Circle Theorems: Definition and Examples | EDU.COMEDU.COMResourcesBlogGuidePodcastPlanBackHomesvg]:size-3.5">Math Glossarysvg]:size-3.5">Circle TheoremsCircle Theorems: Definition and ExamplesTable of ContentsCircle Theorems: Understanding Angles and Relationships in Circles Definition of Circle Theorems

Circle theorems in geometry are statements that prove significant results about circles. These theorems provide important information about various parts of a circle and help us calculate missing angles using established rules. A circle is a locus of points that are equidistant from a fixed point called the center, and different theorems relate to various circle parts such as radius, central angles, tangents, sectors, and chords.

Circle theorems include the alternate segment theorem, the angle at the center theorem, angles in the same segment theorem, angle in a semicircle theorem, chord of a circle theorem, angles subtended by equal chords theorem, cyclic quadrilateral theorem, and tangent theorems. Each theorem establishes specific relationships between angles and other elements of circles, making it easier to solve complex geometric problems involving circles.

Examples of Circle Theorems Example 1: Finding Angles Using the Alternate Segment Theorem Problem:

In the circle given below, triangle ABCABCABC is inscribed in the circle and the tangent DEDEDE meets the circle at the point BBB. Find the measure of angle "xxx" and "yyy".

circle

Step-by-step solution:

Step 1, Find angle xxx using the sum of interior angles in a triangle. We know that the sum of interior angles of a triangle is equal to 180°180°180°.

Step 2, Apply this to triangle ABCABCABC.

∠BAC+∠ACB+∠ABC=180°\angle BAC + \angle ACB + \angle ABC = 180°∠BAC+∠ACB+∠ABC=180°

x+57°+48°=180°x + 57° + 48° = 180°x+57°+48°=180°

Step 3, Solve for xxx.

x=180°−105°x = 180° - 105°x=180°−105°

x=75°x = 75°x=75°

Step 4, Find angle yyy using the alternate segment theorem. According to this theorem, the angle formed between the tangent and the chord through the point of contact equals the angle formed by the same chord in the alternate segment.

Step 5, Apply the theorem to get yyy.

x=y=75°x = y = 75°x=y=75°

Step 6, State the answer. The measure of ∠x∠x∠x and ∠y∠y∠y is 75°75°75°.

Example 2: Using the Angle in a Semicircle Theorem Problem:

In the figure given below, find the value of xxx using the circle theorems.

circle

Step-by-step solution:

Step 1, Identify that ∠ABC∠ABC∠ABC is an angle in a semicircle.

Step 2, Apply the angle in a semicircle theorem. An angle in a semicircle is always a right angle.

m∠ABC=90°m\angle ABC = 90°m∠ABC=90°

Step 3, Use the sum of interior angles of a triangle to find xxx.

m∠BAC+m∠ACB+m∠ABC=180°m\angle BAC + m\angle ACB + m\angle ABC = 180°m∠BAC+m∠ACB+m∠ABC=180°

Step 4, Substitute the known values.

x+37°+90°=180°x + 37° + 90° = 180°x+37°+90°=180°

Step 5, Solve for xxx.

x+127°=180°x + 127° = 180°x+127°=180°

x=180°−127°=53°x = 180° - 127° = 53°x=180°−127°=53°

Step 6, State the answer. The value of xxx is 53°53°53°.

Example 3: Finding the Length of a Chord Problem:

In the given figure, the point OOO is a center of a circle, the radius of a circle is 171717 inches and OP=8OP = 8OP=8 inches. Find the length of the chord ABABAB.

circle

Step-by-step solution:

Step 1, Identify the given information.

OA=OB=17 inchesOA = OB = 17 \text{ inches}OA=OB=17 inches (radius)

OP=8 inchesOP = 8 \text{ inches}OP=8 inches

OP⊥ABOP \perp ABOP⊥AB (perpendicular)

Step 2, Use the Pythagorean theorem in triangle OPBOPBOPB.

OP2+PB2=OB2OP^2 + PB^2 = OB^2OP2+PB2=OB2

82+PB2=1728^2 + PB^2 = 17^282+PB2=172

Step 3, Solve for PBPBPB.

PB2=172−82=289−64=225PB^2 = 17^2 - 8^2 = 289 - 64 = 225PB2=172−82=289−64=225

PB=225=15 inchesPB = \sqrt{225} = 15 \text{ inches}PB=225​=15 inches

Step 4, Apply the chord of a circle theorem. The perpendicular drawn from the center of the circle to a chord bisects the chord.

Step 5, Since OPOPOP is perpendicular to ABABAB, PPP is the midpoint of ABABAB.

AP=PB=15 inchesAP = PB = 15 \text{ inches}AP=PB=15 inches

Step 6, Find the total length of chord ABABAB.

AB=AP+PB=15 inches+15 inches=30 inchesAB = AP + PB = 15 \text{ inches} + 15 \text{ inches} = 30 \text{ inches}AB=AP+PB=15 inches+15 inches=30 inches

Step 7, State the answer. The length of the chord ABABAB is 303030 inches.

Comments(1)HHunterGinaNovember 4, 2025I've used this page to teach circle theorems. The clear defs and examples made it easy for my students to grasp. Great resource!

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