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Maximum: Definition and Example | EDU.COMEDU.COMResourcesBlogGuidePodcastPlanBackHomesvg]:size-3.5">Math Glossarysvg]:size-3.5">MaximumMaximum: Definition and ExampleTable of ContentsUnderstanding Maximum in Mathematics Definition

In mathematics, a maximum is the largest value in a set of numbers or the highest point on a graph of a function. When we find a maximum, we're looking for the biggest number in a group or the highest point a curve reaches. For example, in the set {3, 8, 2, 10, 5}, the maximum value is 10 because it's larger than all other numbers in the set. In everyday life, we use maximums when we need to know the highest temperature of the day, the tallest student in a class, or the largest number of points scored in a game.

There are different types of maximums we might study. A global maximum (or absolute maximum) is the highest value across an entire set or function. A local maximum (or relative maximum) is a value that's higher than all nearby values, but might not be the highest overall. For functions, a maximum can occur at a point where the slope changes from positive to negative, which is a turning point on a graph. Finding maximums is important in many areas of math and helps us solve real-world problems like finding the best price, the most efficient strategy, or the optimal dimensions for an object.

Examples of Maximum in Mathematics Example 1: Finding the Maximum Value in a Set of Numbers Problem:

Find the maximum value in this set of numbers: 151515, 888, 232323, 171717, 444, 191919

Step-by-step solution:

Step 1, Write down all the numbers so you can see them clearly.

151515, 888, 232323, 171717, 444, 191919

Step 2, Start by picking any number as your "current maximum."

Let's start with the first number: 151515 Current maximum = 151515

Step 3, Compare this maximum with the next number in the list.

Next number is 888. Is 888 larger than 151515? No, it's smaller. So our maximum is still 151515.

Step 4, Continue comparing with each number in the list.

Next number is 232323. Is 232323 larger than 151515? Yes, it is! So our new maximum is 232323.

Step 5, Keep going through the list.

Next number is 171717.

Is 171717 larger than 232323? No, it's smaller.

Maximum is still 232323.

Next number is 444.

Is 4 larger than 232323? No, it's smaller.

Maximum is still 232323.

Next number is 191919.

Is 19 larger than 232323? No, it's smaller.

Maximum is still 232323.

Step 6, After checking all numbers, we can give our answer.

The maximum value in the set {151515, 888, 232323, 171717, 444, 191919} is 232323. Example 2: Finding the Maximum Height of a Ball Problem:

A ball is thrown upward with an initial velocity of 202020 meters per second. The height (h)(h)(h) of the ball (in meters) at time ttt seconds is given by the formula h=20t−5t2h = 20t - 5t^2h=20t−5t2. Find the maximum height the ball reaches.

Step-by-step solution:

Step 1, To find the maximum height, we need to find when the ball stops going up and starts coming down.

This happens when the velocity becomes zero.

Step 2, The velocity is the rate of change of height, which we can find by taking the derivative of the height function.

The derivative of h=20t−5t2h = 20t - 5t^2h=20t−5t2 is dhdt=20−10t\frac{dh}{dt} = 20 - 10tdtdh​=20−10t

Step 3, Set the velocity equal to zero to find when the ball reaches its highest point.

20−10t=020 - 10t = 020−10t=0

Step 4, Solve for ttt.

20−10t=020 - 10t = 020−10t=0

−10t=−20-10t = -20−10t=−20

t=2t = 2t=2

So the ball reaches its maximum height at t=2t = 2t=2 seconds.

Step 5, Calculate the maximum height by plugging t=2t = 2t=2 back into the original height formula.

h=20t−5t2h = 20t - 5t^2h=20t−5t2 h=20(2)−5(2)2h = 20(2) - 5(2)^2h=20(2)−5(2)2 h=40−5(4)h = 40 - 5(4)h=40−5(4) h=40−20h = 40 - 20h=40−20 h=20h = 20h=20

Step 6, State your final answer.

The maximum height the ball reaches is 202020 meters, which occurs at 222 seconds after it's thrown. Example 3: Finding the Maximum Value of a Mathematical Expression Problem:

Find the maximum value of y=12x−x2y = 12x - x^2y=12x−x2 for values of xxx between 000 and 121212.

Step-by-step solution:

Step 1, Understand what we're looking for.

We need to find the value of xxx between 000 and 121212 that gives us the largest possible value for yyy.

Step 2, Find where the slope of the function changes from positive to negative.

The slope is given by the derivative: dydx=12−2x\frac{dy}{dx} = 12 - 2xdxdy​=12−2x

Step 3, Set the derivative equal to zero to find where the slope changes.

12−2x=012 - 2x = 012−2x=0 −2x=−12-2x = -12−2x=−12 x=6x = 6x=6

Step 4, Check that this is a maximum (not a minimum) by making sure the second derivative is negative.

The second derivative is d2ydx2=−2\frac{d^2y}{dx^2} = -2dx2d2y​=−2, which is negative. This confirms we've found a maximum.

Step 5, Calculate the maximum value by plugging x=6x = 6x=6 into the original function.

y=12x−x2y = 12x - x^2y=12x−x2 y=12(6)−(6)2y = 12(6) - (6)^2y=12(6)−(6)2 y=72−36y = 72 - 36y=72−36 y=36y = 36y=36

Step 6, Check the endpoints of our range to be sure.

For x=0x = 0x=0: y=12(0)−(0)2=0y = 12(0) - (0)^2 = 0y=12(0)−(0)2=0 For x=12x = 12x=12: y=12(12)−(12)2=144−144=0y = 12(12) - (12)^2 = 144 - 144 = 0y=12(12)−(12)2=144−144=0 Both endpoint values (000) are less than our calculated maximum (363636).

Step 7, State the final answer.

The maximum value of y=12x−x2y = 12x - x^2y=12x−x2 for values of xxx between 000 and 121212 is 363636, which occurs when x=6x = 6x=6. Comments(1)MCMs. CarterSeptember 17, 2025Loved how simple the 'maximum' definition is here! I used it to help my son with his math homework, and he finally got it. The example with {3,7,2} was super clear!

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